-5t^2+14t=8

Solution for -5t^2+14t=8 equation:

-5t^2+14t=8

We move all terms to the left:

-5t^2+14t-(8)=0

a = -5; b = 14; c = -8;
Δ = b2-4ac
Δ = 142-4·(-5)·(-8)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-6}{2*-5}=\frac{-20}{-10}
=+2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+6}{2*-5}=\frac{-8}{-10}
=4/5
$